
#73
May1006, 05:13 PM

P: 306





#74
May1006, 05:57 PM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam1/sp03
Question 23 I did Centripital Acceleration * weight 50 * .5 = 25 is this the right way? 



#75
May1006, 06:32 PM

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#76
May1006, 07:20 PM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam2/fa05 Last question, i still dont get how to set it up incase he asks the same question and wants the resultant velocity
so (1.5*10^5)(8) = (4*1.5*10^5) + (1.5*10^6*X) Is this the setup 



#78
May1006, 07:54 PM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam2/sp05
Question 6 So what i was thinkin is to do it this way so work done by friction = W = *.43*9.8*12 = 50.568 Total Kinetic Energy = MGH + .5 MV^2 = (9.8)(9) + .5 (20^2) = 288.2 288.250.568 = 237.632 Edit: well it works if i dont take in effect the PE of the hill but why not? 



#79
May1006, 08:11 PM

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#80
May1006, 09:05 PM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam1/sp99 Question 25
here was my plan divide the thing into 2 so 55 M on left, 55 M on right do Tan 35 = X / 55 The Height = 38.5114 Okay then i decided to just do 38.5114 = .5 * 9.8 * T^2 T = 2.80 Okay another way (2)(9.8)* 38.5114 = V^2 V = 27.47405 so what i did was divide that be Cos 35 and got 33.53 why am i off? 



#81
May1006, 10:10 PM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam2/fa04
Question 16 So i know that Change in kinetic = Uk g * D So what i did was (22)(9.8) + (9)(9.8) = X * 9.8 *53 wat am i doing wrong 



#82
May1106, 03:33 AM

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#83
May1106, 11:41 AM

P: 306

http://online.physics.uiuc.edu/cgi/c...ice/exam2/fa04
Question 19 So Wnet = 8.6483 Wnet  Force of friction  Force of gravity I did get the above questions right so i know the numbers are right 8.6483 = .5 mV^2 V = 2.9773 The 3 is the ending velocity (2)(2.9773)  (2)(3) = 11.9546 ( Total Momemtum) Fave T = P X (.06) = (11.9546) X = 200 Is this how it is done 



#84
May1106, 12:07 PM

P: 306

WHen it says you Double The Frequency does it Actually mean Multiply it by 2 or does it mean Half it?




#85
May1106, 12:31 PM

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#86
May1106, 12:35 PM

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#87
May1106, 12:55 PM

P: 306

Suppose the mass of the string in the above problem is M0. What is the mass of a new string (in terms of M0 ), if the fundamental frequency of the string is doubled compared to the previous value, but the length and tension in the string are the same as before?
Now does this Mean Frequncy * 2 or frequency / 2 



#88
May1106, 12:56 PM

P: 306





#89
May1106, 12:58 PM

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