 Quote by need help
If I have a initial velocity of 0m/s and an acceleration of .76m/s2 and a distance of 2meters what would my final velocity be?
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[itex] v_{f,x}^2 = v_{i,x}^2 + 2 a_x (x_f-x_i) [/itex] where x_f-x_i is essentially the distance traveled. have you seen this equation before?
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Also I need to find F(net) I know a mu of .15 a time of 5seconds a mass of 5kg and force of gravity equals 49N an normal force equals -49N and force of friction equals -7.35N. I think I'm supposed to use the velocity found in the question above, but I'm not sure and I don't know how. How do I find F(net) with the information I have and what is the answer??
Any help would be greatly appriciated...
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It
The key point is that the magnitude of the friction force is equal to the magnitude of the normal force times the coefficient of kinetic friction [itex] \mu_k[/itex]