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Basic Circuit Analysis - mutual induc |
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| Jun3-06, 05:42 PM | #1 |
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Basic Circuit Analysis - mutual induc
This problem seems so simple, but I CANNOT get the right answer.
Here is the work I've done so far: ![]() I've also attached the work, but if anyone wants to check the links before it gets approved, please be my guest. The books says that the correct answer is: V0 = 2.24 at an angle of -153.43 I don't understand what I'm doing wrong ! |
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| Jun3-06, 11:33 PM | #2 |
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Not exactly the most helpful tip, but you will get the answer in the book (according to the method you used) if the mutual inductance is 2j instead of j.
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| Jun4-06, 02:58 AM | #3 |
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I think you mixed the inductance in your equations. I agree with doodle, if you use j2 you'll get the answer in the back of the book.
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| Jun4-06, 08:39 PM | #4 |
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Basic Circuit Analysis - mutual induc
Why would the mutual inductance term be 2j?
Isn't M defined by as [itex] j1\omega [/itex] ? If I use 2j I get the book's answer, but I don't understand why I should use 2j. |
| Jun5-06, 01:56 AM | #5 |
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I am not sure why you should say that M is defined as j1w. Or perhaps you are trying to say that the question explicitly gave M = j1w?
A quick browse in my Circuit Theory textbook reveals that M depends on the coupling coefficient, k, and then M = k sqrt(L1*L2). |
| Jun5-06, 02:20 AM | #6 |
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Oh sorry about the latex confusion. Yes, the question explicitly said that [itex] M = j1\Omega [/itex]
I typed a small omega instead of a big one. |
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