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Infinity geometric series question |
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| Jun14-06, 07:21 AM | #1 |
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Infinity geometric series question
Hi there everyone!
Have a quick question for you. The question is: The sum to infinity of a geometric series is 9/2 The second term of the series is -2 Find the value of r, the common ratio of the series. I understand that we have to use the sum to infinity of a geometric series formula which is S(infinity) = a/1-r where a is the first term in the series and r is the common ratio. I also understand that s2 = s1*r. We're given the second term....but how do we get a? our first term? Any thoughts?
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| Jun14-06, 07:30 AM | #2 |
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Recognitions:
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if you understand the second term is r times the first term, then you understand the first time is what times the second term?
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| Jun14-06, 09:16 AM | #3 |
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The first term is the second term over r.
Well spotted!! I'll get the hang of this stuff yet!! :)) Thanks very much |
| Jun14-06, 01:26 PM | #4 |
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Infinity geometric series question
So you now know that a= -2/r and that
[tex]\frac{a}{1-r}= \frac{-2}{r(1-r)}= 9/2[/tex] Solve for r. |
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