
#1
Jul1806, 05:44 AM

P: 99

I know the Bayesian formula is given by the ff:
P(EiA) = P(A  Ei) * P (Ei) / summation of P (A  En) * P (En) over n however how do you solve this type of problem: The probability of a person having a disease is 5%, The probability of testing negative in a checkup given that you have a disease is 2% (the test is not accurate, hence this result). The probability of testing positive given that you do not have the disease is 10% Tim takes the test 10 times, only one of which returns positve, what is the probability that Tim has the disease? that is what is P(disease  9 tests results negative and 1 test results positive)? any hints would be great, thanks. 


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