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Adding Net Ionic Equations

by yellowduck
Tags: adding, equations, ionic
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yellowduck
#1
Jul19-06, 08:34 PM
P: 16
This should be easy but I feel there is something I am mission

I need to write the net ionic equations and then add #1 & #2 and compare to #3.

Equation #1 - write net ionic equation for dissolution of solid NaOH in water
Equation: NaOH (s) + H2O --> Na+ (aq) + OH- (aq) + H2O (l)
Net: NaOH (s) --> Na+ (aq) + OH- (aq)
(it says in the book to seperate strong bases such as NaOH but if I do all ions cancel out???)

Equation #2 - write net ionic equation for aqueous soloutions of NaOH & HCl
Equation: NaOH (aq) + HCl (aq) ---> NaCl (aq) + H2O (l)
Net: OH- (aq) + H+ (aq) --> H2O (l)

Equation 3: Solid NaOH and aqueous HCl
Equation: NaOH (s) + HCl (aq) ---> NaCl (aq) + H2O
OH- (s) + H+ (aq) --> H2O (l)

Add #1 & #2
This is where I get lost. I think it should be net equation #2. The difference is in the solid/aqueous state.

thanks
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PPonte
#2
Jul19-06, 08:48 PM
P: n/a
1. Add #1 to #2.

[tex]NaOH \text{(s)} + OH^- \text{(aq)} + H^+ \text{(aq)} \longrightarrow Na^+ \text{(aq)} + OH^- \text{(aq)} + H_2O \text{(l)}[/tex]

2. Delete the common compounds on both members of the equation.

[tex]NaOH \text{(s)} + H^+ \text{(aq)} \longrightarrow Na^+ \text{(aq)} + H_2O \text{(l)}[/tex]
yellowduck
#3
Jul19-06, 09:08 PM
P: 16
Is it possible that I have equation #3 wrong.
Should the net ionic equation look like your final answer above?

PPonte
#4
Jul19-06, 09:44 PM
P: n/a
Adding Net Ionic Equations

Quote Quote by yellowduck
Is it possible that I have equation #3 wrong.
Should the net ionic equation look like your final answer above?
You have #3 correct, I think.

sdekivit
#5
Jul20-06, 02:44 AM
P: 92
Solid NaOH in HCl-solution. The HCl-solution contains [tex]H^{+}[/tex] and [tex]Cl^{-}[/tex] but the solid is just NAOH. So the reaction at 3 should be:

[tex]NaOH(s) + H^{+} \rightarrow Na^{+} + H_{2}O[/tex]
dissolver
#6
Aug6-06, 02:56 PM
P: 16
So if it states solid, then you must write out the entire formula even in the net ionic equation (because it is infered that the solid is not dissolved in the solution)?


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