Monkey on a Tree: Will it be Shot by a Hunter? | Simple Homework Problem

  • Thread starter Thread starter luther_paul
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves a scenario where a monkey is on a branch of a tree, and a hunter aims to shoot it with a rifle. The height of the tree is given as 10 meters, and the hunter is positioned 20 meters away from the tree. The question revolves around whether the monkey will be shot when it falls at the moment the hunter pulls the trigger.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the projectile motion equations and the assumptions necessary for the problem, such as neglecting air resistance and the alignment of the rifle's sights. There is also a debate about the implications of the bullet's trajectory and the monkey's fall.

Discussion Status

The discussion includes various interpretations of the problem, with some participants providing mathematical reasoning and others questioning the assumptions made. While some guidance has been offered regarding the physics involved, there is no explicit consensus on the outcome of the scenario.

Contextual Notes

Participants note the need to assume ideal conditions, such as neglecting air resistance and considering the aiming of the rifle. The initial conditions of the monkey's fall and the bullet's trajectory are also under examination.

luther_paul
Messages
16
Reaction score
0
simple problem for you!

here's a simple homework problem!

a monkey is on a branch of a tree and a hunter aims with his rifle. at that moment when the hunter pulls the trigger, the monkey fell.
will the monkey be shot? assuming the height of the tree is 10 m.. and the hunter is 20m from the tree... assuming that the bullet travels off the barrel at standard velocity of a M16 assault rifle.
 
Last edited:
Physics news on Phys.org
Equation of projectile is
[tex] y=x\tan{\theta}-\frac{gx^2}{2v_o^2cos^2\theta} ...A[/tex]
So for x=20 and tan(theta)=10/20 similarly u can get value of cos(theta) and initial velocity given v0

Also to travel x=20 bullet takes time t given by

[tex] v_0cos{\theta}t=20[/tex] ...1

In this time the monkey would have traveled
[tex]y=10-\frac{gt^2}{2}[/tex] .....2

from 1 & 2 & A

U can conclude that it would hit the (Poor)monkey
 
Actually there are a number of things left unsaid in this problem.

One, you must assume that we can neglect air resistance and friction.

Secondly we must assume that sights on the gun are not set to allow for bullet drop! Since the bullet drops (due to gravity of course), sights are normally set so that the barrel "aims" slightly above the target to allow for the drop over a given distance. Here we must assume that "aiming" at the monkey means that the bullet leaves the barrel along the straight line from the bullet to the monkey.

Assuming those things then the whole point of the question is that the downward acceleration of the bullet and monkey are exactly the same: -g. The fall of the bullet from a straight line will be exactly the same as the fall of the monkey and so the bullet will hit the monkey.
 
but the bulet isn't going in a straight line forward, the tree is 10 up, meaning he's aiming slightly upwards.
 
It doesn't matter that the straight line is not horizontal. The bullet's initial vertical velocity would take the bullet straight to the monkey, the monkey's initial velocity is 0. The vertical acceleleration of both monkey and bullet is the same.

(himanshu121's explanation is completely correct, just more than is necessary.)
 
I think I had the same exact question on one of my physics test. I really hated that test. Anyway, what Himanshu said was right. At least, it was what my teacher told me was right.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 18 ·
Replies
18
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 2 ·
Replies
2
Views
6K