#1
Aug506, 04:00 AM

P: n/a

I just found Max's question on the 2 Lagrangians giving the same EOM's
(8 Mar 06). [ Mod. note: The poster is probably referring to the message news:1141408564.026625.242830@u72g2000cwu.googlegroups.com http://groups.google.ca/group/sci.ph...dbe8734370c10d Please quote when replying. ik ] As I didn't see a reaction , here is one ..... Using the identity (x+y)^2 = x^2 + y^2  2 x y the 2 Lagrangians are connected by F = m/2 (dx  dy)^2 a/2 (x  y) ^2 where dX stands for x_dot. It is easy to see that F is the difference between the energy (hamiltonian) of the two formulations. F = H  H' , hence F = d [ (H  H') t] and the textbook property is satisfied. Sjarel 


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