- #1
xto
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The question is
a volume of 2.2m^3 of air at inital conditions of 1.2bar and 303K undergoes the following process to complete a cycle :
i)isothermal compresssion from state 1 through a volumetric compression ration of 6 to state 2
ii) isobaric expansion from state 2 back to the initial volume thus reaching state 3
iii) isochoric cooling from state 3 back to the original pressure to reach state 1
Q1) Find the mass of air present
so i use the formula PV=nRT
P=1.2bar
V=2.2M^3
n=?
R=6
T=303K
so i need to find N so i got 2.64 = 1818N
which N is 1.452x10^-3
which is total not the mass of the air , please help
a volume of 2.2m^3 of air at inital conditions of 1.2bar and 303K undergoes the following process to complete a cycle :
i)isothermal compresssion from state 1 through a volumetric compression ration of 6 to state 2
ii) isobaric expansion from state 2 back to the initial volume thus reaching state 3
iii) isochoric cooling from state 3 back to the original pressure to reach state 1
Q1) Find the mass of air present
so i use the formula PV=nRT
P=1.2bar
V=2.2M^3
n=?
R=6
T=303K
so i need to find N so i got 2.64 = 1818N
which N is 1.452x10^-3
which is total not the mass of the air , please help