
#1
Sep1606, 10:06 PM

P: 56

The sine of 45 degrees is equal to root two over two or approximately.7071. I was playing around on my calculator when i stumbled upon the resemblance that sine45 degrees is either equal to or extremely close to the sum from one to fifty of the (square root of x)/10. Is there anything here or just something I'm missing




#2
Sep1606, 10:41 PM

P: 135

Hmmm, maybe you should check your calulation again. To me it looks like Sum [ sqrtx/10 ] x = 1 to 50 is roughly equal to 24.




#3
Sep1706, 07:18 AM

P: 361

yeah, i also get 23.903580060352073




#4
Sep1706, 04:27 PM

P: 56

sine 45 degrees
yau guys are righti was using a ti30 and it was a bit confusing as to the notation but what i ended up doing was (root 50)/10 not sum from 1 to 50it was late last nightmy apologies




#5
Sep1706, 05:38 PM

P: 135

Ah, well in that case [tex] \sqrt{50}/10 = 5 \sqrt{2}/10 = \sqrt{2}/2 = \sin(45^\circ) [/tex]



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