SecondOrder Nonhomogenous Linear Differential Equations

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SUMMARY

The discussion focuses on solving second-order nonhomogeneous linear differential equations using the method of variation of parameters. The specific equations addressed are y'' + 2y' + 2y = e^-x and 2y'' + y' = cos 2x. The user initially struggles with isolating the parameters u'sub1 and u'sub2 but ultimately resolves both equations. Key insights include the importance of isolating parameters and correctly substituting values to simplify the equations.

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  • Understanding of second-order linear differential equations
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  • Basic knowledge of differential calculus
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wubie
Hello,

First here is the question that I am supposed to solve:

Solve the following nonhomogeneous differential equations:

b) y'' + 2y' + 2y = e^-x

c) 2y'' + y' = cos 2x.


I am supposed to be using the method of variation of parameters to solve these equations. What my problem is I end up getting to a point where I have two equations in which I should be able to solve for the derivative of parameter one (u'sub1) and the derivative of parameter two (u'sub2). Unfortunately I am getting stuck. And I am not sure why.

For b) I have the following two equations:

u'sub1 ysub1 + u'sub2 ysub2 = 0 = u'sub1 e^-x + u'sub2 xe^-x

and the particular equation

u'sub2 - u'sub2 x + usub2 x - u'sub1 + usub1 = 1

From these I am supposed to find u'sub1 and u'sub2 and eventually come to find usub1 and usub2.

Now when I solve for

u'sub1 e^-x + u'sub2 xe^-x = 0

I get u'sub1 = (-u'sub2 xe^-x)/e^-x = -u'sub2 x

I then sub. into the other equation for u'sub1

u'sub2 - u'sub2 x + usub2 x - u'sub1 + usub1 = 1

becomes

u'sub2 - u'sub2 x + usub2 x + u'sub2 x + usub1 = 1

which becomes

u'sub2 + usub2 x + usub1 = 1

But I am stumped here. How do I solve for u'sub2 when I still have usub2 and usub1? I know I am missing something incredibly obvious. I just can't seem to know what.

For question b) I am having similar problems - still trying to solve for u'sub1 and u'sub2.


Update: I have figured out question c). I am still working on part b however.

2nd Update: I figured out question b as well. Thanks to all who took the time to look at my post.

Cheers.
 
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Hello,

Glad to hear that you were able to figure out both parts of the question. The method of variation of parameters can be tricky, so it's understandable that you got stuck at first. Here are some tips that might help you in the future:

1. When solving for u'sub1 and u'sub2, make sure to isolate them on one side of the equation and all other terms on the other side. This will make it easier to solve for them individually.

2. When substituting u'sub1 into the other equation, make sure to substitute it as a whole, not just part of it. In your example, you only substituted u'sub1 as "u'sub2 x", but you should have substituted it as "-u'sub2 x". This will result in a different equation and may help you solve for u'sub2.

3. Remember to use the initial conditions given in the question to solve for the constants u'sub1 and u'sub2. These conditions will help you determine the specific values of the parameters and complete the solution.

I hope these tips will help you in your future problem-solving. Keep practicing and you will become more comfortable with the method of variation of parameters. Good luck!
 

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