#1
Oct1106, 02:39 PM

P: n/a

Consider a non interacting field, and a one particle excitation there.
We calculate the propagator using path integral, and to do this we add all the trajectories; most of them of course violate classical mechanics preservation laws and they are weighted down. Well, usual business. Now, I wonder, can we tell that in some sense the trajectories we are contemplating are offshell? And if so, can we tell that particle propagation is always "virtual"? Alejandro 


#2
Oct1106, 02:39 PM

P: n/a

"Alejandro Rivero" <Al.Rivero@gmail.com> wrote in message
news:ab741577.0504190725.2fd7e1c8@posting.google.com...  Consider a non interacting field, and a one particle excitation there.  We calculate the propagator using path integral, and to do this we add  all the trajectories; most of them of course violate classical  mechanics preservation laws and they are weighted down. Well, usual  business.   Now, I wonder, can we tell that in some sense the trajectories we are  contemplating are offshell? And if so, can we tell that particle  propagation is always "virtual"? I think in the current interpretation a "real" particle has no "virtualness" when "noninteracting". But I think we have to consider that there is really no such thing as a "particle field" or even field that is noninteracting. IOW, it is impossible to have a "bare" fermion. So maybe the first part of your statement; "Consider a non interacting field..." is not possible to consider really. What would be an example of a real physical noninteracting field? This seems to be very abstract to me. FrediFizzx 


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