Charge equivalent to a gravitational black hole???

Ray Tomes

The coloumb force is about 10^40 times greater than
gravity for a pair of elementary particles.
(For p+e it is <10^40 but for p+p it is near 10^43).

The mass of a nucleon relative to its radius is about
a factor of 10^44 too small to create a black hole.

I guess this is a sort of new way of looking at the
LNH (Large Numbers Hypothesis). Perhaps the second
item above is a new addition to the ~10^40 club?

When put this way, it strongly suggests to me that
there ought to be a charge "black hole" equivalent
to the gravity black hole. In that case, nucleons
would appear to be seriously near to this already
given the above ratios.

After all, the bending of light by charge effects
happens substantially in ordinary matter in ordinary
little things whereas gravitational light bending
requires huge aglomerations of matter to achieve.

Has this idea ever been investigated?

Does this relate to anything in standard physics?

Thanks
Ray Tomes
http://ray.tomes.biz/

David M. Palmer

In article <d8ooi8$j13$1@lust.ihug.co.nz>, Ray Tomes
<ray@tomes.remove.biz> wrote:

> When put this way, it strongly suggests to me that
> there ought to be a charge "black hole" equivalent
> to the gravity black hole. In that case, nucleons
> would appear to be seriously near to this already
> given the above ratios.
....
> Does this relate to anything in standard physics?

If you have an atomic nucleus with Z > ~150 it causes a 'sparking of
the vacuum', where an electron-positron pair can be formed so that the
electron falls into the nucleus, the positron is ejected, and the whole
system has less energy than before.

This is similar to Hawking radiation.

--
David M. Palmer dmpalmer@email.com (formerly @clark.net, @ematic.com)