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Mass and strong interaction. |
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| Oct11-06, 03:32 PM | #1 |
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Mass and strong interaction.
Hello,
Several months ago, Frank Wilczek wrote two articles about F=ma (appearing in "Physics Today" Oct and Dec, 2004). He thinks it's a culture to accept such a formula. It seems to me he tried to understand the origin inertia mass from the view point of strong interaction. I am just curious whether we can trace the origin of mass back to the interaction of elementary particles. In other words, why we need some force to accelerated something (e.g a neutron) in vacuum from the view point of QFT? Is it due to some kind of interaction preventing the acceleration of the neutron? Or is it because of the structure of space-time? Is this related to Higgs? Thanks! DW |
| Oct11-06, 03:33 PM | #2 |
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On 2005-06-23, DW <an_eyas@yahoo.com.cn> wrote:
> Hello, > Several months ago, Frank Wilczek wrote two > articles about F=ma (appearing in "Physics Today" > Oct and Dec, 2004). He thinks it's a culture to > accept such a formula. It seems to me he tried to > understand the origin inertia mass from the view > point of strong interaction. I am just curious whether we > can trace the origin of mass back to the interaction > of elementary particles. In other words, why we need some > force to accelerated something (e.g a neutron) in vacuum from > the view point of QFT? Is it due to some kind of interaction > preventing the acceleration of the neutron? Or is it because > of the structure of space-time? Is this related to Higgs? >From the point of view of QFT, inertial mass is the minimum energy m between the ground state and an excited state of a quantum field. Sometimes m is also referred to as a gap. A single particle corresponds to a small excitation on top of the ground state. Think first excited state of a harmonic oscillator compared to its ground state. Relativistic invariance these states be labeled by momentum and the energy be E=sqrt(p^2+m^2) or E^2-p^2 = m^2. This translates into single particle states being described by solutions of a wave equation of the form box(phi) = 0, where "box" is the d'Alambertian. The type of wave function phi depends on the type of quantum field under consideration. Locality (or rather cluster separability) garantees that several particle states containing widely separating wave packets obey the same equation locally. Once interactions are taken into account, the joint wave equation describing a multi-particle system can no longer be factored into individual wave equations and becomes coupled (think multiparticle interacting Schroedinger equation). The classical limit is obtained by applying the WKB approximation, which tells us that the phase of the wave function satisfies the Hamilton-Jacobi equation. The characteristics of this first order scalar PDE are the trajectories of the solution of the relativistic Hamiltonian dynamical system with Hamiltonian of the form H = (E^2-p^2 - m^2) + (other particle) + (interactions) = 0. If the non-relativistic limit is taken, the Hamiltonian formulation turns into the more familiar H = p^2/2m + (other particles) + (interactions), where p is now the non-relativistic momentum p = mv. From here Newton's second law F(due to interactions) = dp/dt = m dv/dt is recovered in the usual way. To review. The m in the F=ma comes from the relativistic relation E^2-p^2 = m^2. This relation comes from the wave equation satisfied by few particle states. This wave equation is derived from the spectrum of the excitations of a quantum field. The specific form of the spectrum is due to relativistic invariance and the existence of a minimum excitation energy (the gap). The next question is "why the gap"? And the answer is not really known. It is hypothesized that all elementary particles in the standard model start out as massless (no gap), but then acquire a mass of the form "(expectation value of Higgs field) x (coupling constant to Higgs field)". Hope this helps. Igor |
| Oct11-06, 03:33 PM | #3 |
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DW wrote: > In other words, why we need some > force to accelerated something (e.g a neutron) in vacuum from > the view point of QFT? Is it due to some kind of interaction > preventing the acceleration of the neutron? Or is it because > of the structure of space-time? Is this related to Higgs? This is called "Newton's 1-st law": a particle does not accelerate (moves with a constant velocity) if there are no other particles around which can interact with it. If there are other particles around, then normally the first particle feels a force, i.e., accelerates. Particle's mass m connects acceleration with force. Most naturally, parameter m (along with spin) appears in the Wigner's classification scheme of elementary particles as unitary irreducible representations of the Poincare group. Eugene Stefanovich. |
| Oct11-06, 03:35 PM | #4 |
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Mass and strong interaction.
Igor Khavkine wrote:
> On 2005-06-23, DW <an_eyas@yahoo.com.cn> wrote: > >>Hello, >> Several months ago, Frank Wilczek wrote two >>articles about F=ma (appearing in "Physics Today" >>Oct and Dec, 2004). He thinks it's a culture to >>accept such a formula. It seems to me he tried to >>understand the origin inertia mass from the view >>point of strong interaction. I am just curious whether we >>can trace the origin of mass back to the interaction >>of elementary particles. In other words, why we need some >>force to accelerated something (e.g a neutron) in vacuum from >>the view point of QFT? Is it due to some kind of interaction >>preventing the acceleration of the neutron? Or is it because >>of the structure of space-time? Is this related to Higgs? > > >>From the point of view of QFT, inertial mass is the minimum energy m > between the ground state and an excited state of a quantum field. > Sometimes m is also referred to as a gap. A single particle corresponds > to a small excitation on top of the ground state. Think first excited > state of a harmonic oscillator compared to its ground state. > > Relativistic invariance these states be labeled by momentum and the > energy be E=sqrt(p^2+m^2) or E^2-p^2 = m^2. This translates into single > particle states being described by solutions of a wave equation of the > form box(phi) = 0, where "box" is the d'Alambertian. The type of wave > function phi depends on the type of quantum field under consideration. > Locality (or rather cluster separability) garantees that several > particle states containing widely separating wave packets obey the same > equation locally. > > Once interactions are taken into account, the joint wave equation > describing a multi-particle system can no longer be factored into > individual wave equations and becomes coupled (think multiparticle > interacting Schroedinger equation). > > The classical limit is obtained by applying the WKB approximation, which > tells us that the phase of the wave function satisfies the > Hamilton-Jacobi equation. The characteristics of this first order scalar > PDE are the trajectories of the solution of the relativistic Hamiltonian > dynamical system with Hamiltonian of the form > > H = (E^2-p^2 - m^2) + (other particle) + (interactions) = 0. > > If the non-relativistic limit is taken, the Hamiltonian formulation > turns into the more familiar > > H = p^2/2m + (other particles) + (interactions), > > where p is now the non-relativistic momentum p = mv. From here Newton's > second law F(due to interactions) = dp/dt = m dv/dt is recovered in the > usual way. > > To review. The m in the F=ma comes from the relativistic relation > E^2-p^2 = m^2. This relation comes from the wave equation satisfied by > few particle states. This wave equation is derived from the spectrum of > the excitations of a quantum field. The specific form of the spectrum is > due to relativistic invariance and the existence of a minimum excitation > energy (the gap). > > The next question is "why the gap"? And the answer is not really known. > It is hypothesized that all elementary particles in the standard model > start out as massless (no gap), but then acquire a mass of the form > "(expectation value of Higgs field) x (coupling constant to Higgs field)". Expanding on my previous post let me suggest a different logic of introducing mass, force, and acceleration in QFT. 1. Elementary particles are described by unitary irreducible representations of the Poincare group. They are characterized by two parameters (according to two Casimir operators of the Poincare group): m (mass) and s (spin). Wigner, 1939. 2. Particle position is described by the Newton-Wigner (1949) operator r. In a multiparticle non-interacting system, the commutators of r and p (momentum) with the Hamiltonian H_0 are [r, H_0] = iv [p, H_0] = 0 so that r(t) = exp(iHt) r(0) exp(-iHt) = r + vt p(t) = p(0) i.e., each particle moves with constant velocity (v = p/sqrt(p^2 + m^2)), which is Newton's 1st law. 3. In the presence of interaction, the multiparticle Hamiltonian is H = H_0 + V (Dirac, 1949), where V depends on positions and momenta of all particles in the system (ignore for a moment creation/annihilation terms, they don't change anything, in principle, see below). The time derivative of p then becomes dp/dt = -i [p, H] = dV/dr (1) The operator F = dV/dr is called "force" (by definition). 4. In the non-relativistic limit p = mv, and eq. (1) yields a = dv/dt = F/m which is the 2nd Newton's law (a is acceleration). 5. Creation and annihilation of particles are described by terms in V that do not commute with the particle number operator. They can be added to eq. (1). The most prominent effect would be the appearance of "radiation reaction" forces due to emission of photons by accelerated charges. Eugene. |
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