## Baryons as Third Rank Antisymmetric Tensors

Hello again:

I just posted some further materials at
http://home.nycap.rr.com/jry/FermionMass.htm, regarding my very strong
suspicion that baryons are third rank antisymmetric tensors, including the
basic Feynman and scattering diagrams for a third rank antisymmetric tensor
which you will see seem to be suggestive of a baryon.

Jay.
_____________________________
Jay R. Yablon
Email: jyablon@nycap.rr.com

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 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl

## Baryons as Third Rank Antisymmetric Tensors

You mean, they are pseudovectors. This would mena their Dirac equation
is

(ym dm - M y5) psi = 0

Are you claiming that?

-drl

 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 You mean, they are pseudovectors. This would mena their Dirac equation is (ym dm - M y5) psi = 0 Are you claiming that? -drl
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.
 "DRLunsford" wrote in message news:1129856562.750023.128180@o13g2000cwo.googlegroups.com... > You mean, they are pseudovectors. This would mena their Dirac equation > is > > (ym dm - M y5) psi = 0 > > Are you claiming that? > > -drl Not necessarily. What I am saying is that if one takes the third rank antisymmetric tensor typically associated with P^uvt = F^uv;t + F^vt;u + F^tu:v which is zero for an abelian fields but can become non-zero for a non-Abelian field due to non-linear boson-boson interactions, that the question then arises, "what is the nature of this third rank object P^uvt when it becomes non-zero?" If one carries through the mathematical development, and uses propagator theory to relate currents to vector bosons (the inverse of the momentum space of the wave equation for a vector boson interacting with a current source), that it turns out that P^uvt inherently contains three fermion currents, regardless of the rank of the Yang Mills group that is, SU(N) for any N. (Maybe other than simple Lie algebras too, but I've not explored those.) The fact that these three-fermion-current sources naturally emerge from P^uvt = F^uv;t + F^vt;u + F^tu:v, leads me to suspect that these P^uvt are closely connected to baryons. That is as far as I have gone to date; a final "proof" would be to derive a three-current object which has the right quantum number to be, say, a proton or a neutron. But just the fact that P^uvt can be shown to contain three distinct J^u current as a general matter is, to me, very intriguing. My home page at http://home.nycap.rr.com/jry/FermionMass.htm shows some of the "flavorless" and "colorless" Feynman diagrams that arise from this analysis. That is, these show just the bare properties of these P^uvt objects, irrespective of their flavor and color quantum numbers. Thanks for your reply. Jay.

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