#1
Oct2706, 10:09 AM

P: n/a

Let [tex]\begin{gather*}A_n\end{gather*}[/tex] be an nxn matrix with the matrixelement [tex]\begin{gather*}a_ik\end{gather*}[/tex]=i+k, i, k = 1, ... ,n. Decide for every value the ndeterminant [tex]\begin{gather*}D_n\end{gather*}[/tex] = det([tex]\begin{gather*}A_n\end{gather*}[/tex]). Donīt forget the value of n=1.
We are two guys here at home that donīt get it right. What shall we start with? We are both newbies on this! Thanks in advance Perrry 



#2
Oct2706, 07:24 PM

P: 16

Consider a matrix [tex]A_n[/tex] such as the one you described with [tex]n \geq 3[/tex].
Look at the columns of [tex]A_n[/tex]: the first column, [tex]c_1[/tex] looks like: [tex]c_1=(2,...,n+1)^T[/tex] the next column looks like [tex]c_2=(3,...,n+2)^T[/tex] and the third column looks like [tex]c_3=(4,...,n+3)^T[/tex]. Since we took [tex]n \geq 3[/tex] we know that we can always get [tex]c_1,c_2,c_3[/tex]. Observe that: [tex]c_3c_2=c_2c_1=(1,...,1)^T[/tex] Therefore, since [tex]c_3+c_1=2c_2[/tex] we have that the columns are linearly dependent. Does this say anything about the determinant? 


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