## Newton's gravity and quantum entangled systems

It is widely assumed that Newton's gravity requires
"action at a distance", and it was argued to favor
the more accurate general relativity theory. But, it
is still possible to become reconciled with Newton's
gravity, if we consider bodies in a gravitational
systems as quantum entangled.

Imagine gravitons propagate at speed of light in the
vacuum. So, two orbiting bodies can be continuously
entangling, by means of exchanging those carrier
particles. A graviton wouldn't need to carry complete
classical information, but quantum information. You can
encode, for instance, a constant distance d between two
orbiting bodies, by means of quantum information. It is
not necessary to duplicate that value d, with one copy
residing in each orbiting system. Both systems can share
the unique value d.

Suppose that constant orbiting distance d can be encoded
in 1 bit of classical information (of course, a distance
larger than Planck length would require more than 1 bit
of information to be suitably encoded). In that scenario,
two entangled systems sharing 1 bit of information, means
each one only needs to send 1/2 bit to the other at speed
of light in the vacuum for state updates, but they still
can be instantaneously aware of any perturbation of distance
d, because that distance d is quantum shared. The amazing
result is that, although the quantun information could be
constantly updated at speed of light, by means of graviton
exchanges, the response action to any perturbation could
start instantaneously.

And that would be the "mysterious action at a distance" that
Newton's gravity would require.

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 Just G. Waller wrote: > It is widely assumed that Newton's gravity requires > "action at a distance", and it was argued to favor > the more accurate general relativity theory. But, it > is still possible to become reconciled with Newton's > gravity, if we consider bodies in a gravitational > systems as quantum entangled. > > Imagine gravitons propagate at speed of light in the > vacuum. So, two orbiting bodies can be continuously > entangling, by means of exchanging those carrier > particles. Suppose we use this gravitation theory to analyse a binary system; call the two orbiting bodies A and B. Then the gravitational force on body A would point not at the current position of B, but rather at where B was when the gravitons were emitted. This means the force would point *behind* the instantaneous direction vector, leading to an effective drag force proportional to v/c. Thus the system would spiral together quite rapidly. Observationally, this drag force isn't seen in the solar system, where (for example) the Earth has orbited the sun at about the same orbital radius for 4.5 Gyr or so. [In general relativity the v/c drag force cancels out, as do the the (v/c)^2, the (v/c)^3, and the (v/c)^4 terms. The leading-order drag force is gravitational radiation emission, proportional to (v/c)^5.] ciao, -- -- "Jonathan Thornburg -- remove -animal to reply" Max-Planck-Institut fuer Gravitationsphysik (Albert-Einstein-Institut), Golm, Germany, "Old Europe" http://www.aei.mpg.de/~jthorn/home.html "Washing one's hands of the conflict between the powerful and the powerless means to side with the powerful, not to be neutral." -- quote by Freire / poster by Oxfam

## Newton's gravity and quantum entangled systems

Jonathan Thornburg -- remove -animal to reply wrote:
> Just G. Waller <wallermax@hotmail.com> wrote:
> > It is widely assumed that Newton's gravity requires
> > "action at a distance", and it was argued to favor
> > the more accurate general relativity theory. But, it
> > is still possible to become reconciled with Newton's
> > gravity, if we consider bodies in a gravitational
> > systems as quantum entangled.
> >
> > Imagine gravitons propagate at speed of light in the
> > vacuum. So, two orbiting bodies can be continuously
> > entangling, by means of exchanging those carrier
> > particles.

>
> Suppose we use this gravitation theory to analyse a binary system;
> call the two orbiting bodies A and B. Then the gravitational force
> on body A would point not at the current position of B, but rather
> at where B was when the gravitons were emitted. This means the
> force would point *behind* the instantaneous direction vector,
> leading to an effective drag force proportional to v/c. Thus the
> system would spiral together quite rapidly.
>

Why could a photon reach body B in its current position,
but a graviton could not?. I've only hypothetized that a graviton
might travel in null geodesics like any photon does, and
at the same constant speed c. Is it so bad to suspect a
graviton could be an "amazing" spin-1/2 boson?.

 Jonathan Thornburg -- remove -animal to reply wrote: > Suppose we use this gravitation theory to analyse a binary system; > call the two orbiting bodies A and B. Then the gravitational force > on body A would point not at the current position of B, but rather > at where B was when the gravitons were emitted. This means the > force would point *behind* the instantaneous direction vector, > leading to an effective drag force proportional to v/c. Thus the > system would spiral together quite rapidly. That would be true if a graviton would carry the whole gravitational force information, but recall, I speak about a "quantum gravitational entangled system". We are dealing with quantum information. So, the new gravitational force would not be effective until both gravitons, one from A and the other from B, have been exchanged, producing a correlation, a new entanglement. And that correlation would be manifested in opposite gravitational attractive forces.