Solving Circuits with the Nodal Method: Finding Va

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SUMMARY

The discussion focuses on solving circuits using the nodal method, specifically addressing the equation for node A: (90-Va)/20 - (Vb-Va)/3 + Va/20 - Ia = 0, where Ia is given as 6 A. The participants clarify that with two unknowns (Va and Vb), the equation cannot yield specific values but can express one variable in terms of the other. The final derived relationships are Va = 9/2 + Vb and Vb = Va/3 - 9/2, indicating a direct dependency between the two node voltages.

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nodal voltage??

im not real sure on how solve circuits using the nodal method. I've got an equation for node a but i don't know how to solve it. here's the equation
(90-Va)/20 - (Vb-Va)/3 + Va/20 - Ia = 0

thats at node a. how do i solve this?
Ia = 6 A
 
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What kind of circuit u are dealing Will u pls provide the pic
 
Taking Ia= 6, you still have two unknown quantities in your equation: (90-Va)/20 - (Vb-Va)/3 + Va/20 - 6 = 0 so you can't "solve" it for specific values. You could solve for either Va or Vb "in terms of" the other.

(90-Va)/20= 9/2- Va/20 and (Vb- Va)/3= Vb/3- Va/3 so simply multiplying the terms in parentheses gives

9/2- Va/20- Vb/3+ Va/3+ Va/20- 6= 0.

The "-Va/20" and "+ Va/20" terms cancel so

Va/3- Vb/3- 12/2+ 9/2= 0 or Va/3- Vb/3= 3/2.

Then Va= 3(3/2+ Vb/3)= 9/2+ Vb or Vb= -3(3/2- Va/3)= Va/3- 9/2.

You might just need Va- Vb= 9/2.
 

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