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Magnetic dipole moment of a sphere |
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| Dec25-06, 04:41 PM | #1 |
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Magnetic dipole moment of a sphere
1. The problem statement, all variables and given/known data
Find the magnetic dipole moment of a spherical shell of radiu R carrying a uniform surface charge sigma, set spinning at angular velocity omega. 2. Relevant equations [tex] \vec{m} = \frac{1}{2} \int_{S} \vec{r'} \times \vec{K} (\vec{r'}) da' [/tex] 3. The attempt at a solution So we gotta figure out the surface charge density (since it is a spherical shell) [tex] K = \sigma v [/tex] and [tex] v = \omega times R [/tex] this is where i am doubtful... the angle between v and R varies from 0 to 2 pi so this cross product is not unique... or am i thinking about this the wrong way?? please help! |
| Dec26-06, 11:08 AM | #2 |
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Recognitions:
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You are right that the angle changes but v will always point in the correct direction. The changing angle ([tex]sin(\theta)[/tex]) accounts for the "azimuthal radius", that is, distance from the spin axis z to the shell measured parallel to the xy plane, that changes with polar angle. That distance is also the r you need to use in your integral.
BTW, polar angle only varies from 0 to [tex]\pi[/tex] |
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