Is x^3 - x + 1 an Even, Odd, or Neither Function?

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Discussion Overview

The discussion centers on determining whether the function x^3 - x + 1 is classified as even, odd, or neither. Participants explore the properties of the function through graphical interpretation and mathematical definitions, focusing on symmetry and polynomial characteristics.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant suggests that the function appears symmetric about the origin, leading to the hypothesis that it might be an odd function.
  • Another participant provides definitions for even and odd functions, indicating that testing f(-x) against f(x) and -f(x) is necessary for classification.
  • A different participant notes that odd functions exhibit rotational symmetry, while even functions are symmetric about the vertical axis.
  • One participant argues that since f(0) is not equal to 0, the function cannot be odd and asserts that it is also not even, referencing a property of polynomials regarding the parity of their powers.

Areas of Agreement / Disagreement

Participants express differing views on the classification of the function, with no consensus reached on whether it is even, odd, or neither.

Contextual Notes

Some assumptions about the properties of polynomials and their symmetry are discussed, but the implications of these assumptions remain unresolved.

Caldus
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Is the function x^3 - x + 1 even, odd, or neither? When I graphed this, it looked like it was symmetric about the origin, so I thought that it might be an odd function. Either that or it is neither?
 
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A function is even if:

f(-x) = f(x)

A function is odd if:

f(-x) = -f(x)

So to figure out if it's even of odd, plug in -x in place of x and compare it to the original.

cookiemonster
 
Look at graph

Also I believe that odd fuctions are rotationaly symetric while even fuctions are symetic on the vertical line. (When a graph is fliped horizontally over it)
 
f(0) isn' 0 so it certainly isn't odd, and clearly it isn't even.

hint: a polynomial in x is even (odd) iff the powers of x are all even (odd)
 

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