Parametric Curve: Solving & Graphing

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SUMMARY

The discussion focuses on solving and graphing the parametric equations x = e^t and y = e^-t. The user successfully derives the Cartesian equation by solving for t in terms of y, resulting in t = -ln(y) and subsequently substituting this into the equation for x, yielding x = e^(-ln(y)). The conversation also touches on graphing techniques and identities that may assist in visualizing the curve, including the multiplication of x and y and logarithmic properties.

PREREQUISITES
  • Understanding of parametric equations
  • Knowledge of logarithmic identities
  • Familiarity with exponential functions
  • Basic graphing skills
NEXT STEPS
  • Learn how to derive Cartesian equations from parametric equations
  • Study graphing techniques for exponential functions
  • Explore the properties of logarithms and their applications in graphing
  • Investigate the use of software tools like Desmos for visualizing parametric curves
USEFUL FOR

Mathematicians, students studying calculus or algebra, and anyone interested in understanding and graphing parametric curves.

Caldus
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Another question...

If I were given these equations:

x = e^t
y = e^-t

Then I have to find the cartesian product for this parametric curve and then I have to sketch the graph of the curve. So here's the cartesian product I came up with:

Solve for t in y, so:

y = e^-t
ln y = ln e^-t
ln y = -t
t = - ln y

Then plug into the x part:

x = e^-ln y

Is that part correct?

I have no idea how to graph this...

Help appreciated.
 
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Do you know any identities applicable to it?
 
Simple method: u^{-r}= 1/u^r
slightly longer metheod, try multiplying x and y together!

or:

-log(p) = log(1/p)
e^log(w)=w

any of those help?
 

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