What is the thrust of the engine?

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Homework Help Overview

The discussion revolves around a rocket's thrust and exhaust ejection rate, focusing on the principles of momentum and thrust calculations in the context of rocket propulsion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between thrust, mass, and acceleration, with some attempting to apply the thrust equation T = ma. Others question the definition of exhaust rate and its relation to thrust, indicating confusion about the units involved.

Discussion Status

Some participants have provided guidance on using momentum principles and the relationship between thrust and exhaust rate. Multiple interpretations of how to approach the problem are being discussed, particularly regarding the calculations for exhaust ejection rate.

Contextual Notes

Participants are navigating the complexities of thrust calculations while considering the effects of gravitational forces and the assumptions made in the problem setup. There is an ongoing discussion about the definitions and relationships between thrust, mass flow rate, and exhaust velocity.

NanoTech
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A rocket is moving away from the solar system at a speed of 6.0 x 10^3 m/s. It fires its engine, which ejects exhaust with a speed of 3.0 x 10^3 m/s relative to the rocket. The mass of the rocket at this time is 4.0 x 10^4 kg, and its acceleration is 2.0 m/s/s.

A) What is the thrust of the engine?

I thought to use the equation T = ma ? T = (4.0 x 10^4 kg)(2.0m/s/s) = 8.0 x 10^4 N.

B) At what rate, in kilograms per second, is exhaust ejected?

I'm stumped on this one, I thought that's what Thrust was?

I thought to maybe use the equation: Vf-Vi = Vrel ln(Mi/Mf) but i don't even know how to use it in this situation... Any help would be great, thanks! ~Dave
 
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I think you need to use momentum.
 
Originally posted by NanoTech
A) What is the thrust of the engine?

I thought to use the equation T = ma ? T = (4.0 x 10^4 kg)(2.0m/s/s) = 8.0 x 10^4 N.
Right. (Assuming that the gravitational force is negligible and that the thrust is the only force on the rocket.)
B) At what rate, in kilograms per second, is exhaust ejected?

I'm stumped on this one, I thought that's what Thrust was?
How could an exhaust rate be equal to a force? The units don't match.

Anyhow, thrust is given by Vrel*dM/dt.
 
ok, so for part B. i take the derivative of the mass, then multiply it by the Vrel. thanks. ~Dave
 
Originally posted by NanoTech
ok, so for part B. i take the derivative of the mass, then multiply it by the Vrel.
For part B you are to find the exhaust rate, which is dM/dt. Set the thrust equal to what you found in part A, then solve for dM/dt.
 

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