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Matrices in reduced rowechelon form 
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#1
Feb907, 12:26 AM

P: 62

1. The problem statement, all variables and given/known data
Determine which of the matrices below are in reduced rowechelon form: a) 1_2_0_2_0 0_0_1_3_0 0_0_1_4_0 0_0_0_0_1 b) 0_1_2_0_3 0_0_0_1_4 0_0_0_0_0 c) 1_2_0_3 0_0_0_0 0_0_1_2 d) 0_1_2_3_4 2. Relevant equations 3. The attempt at a solution Okay, so I know for sure that (a) is not in reduced rowechelon form because the leading one in row 2 had a nonzero value in its column. (b) is in reduced rowechelon form. (c) is the one I'm most curious about. I feel that since there is a leading 1 in row 3, but that there is no leading 1 in row two (and to the left at that) that it's not in reduced rowechelon form, is this correct? (d) I feel confident is in reduced rowechelon form. Are all my thoughts correct? 


#3
Feb907, 08:40 AM

P: 62

To reduce it would you switch row 2 and 3?



#4
Feb907, 09:10 AM

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P: 3,220

Matrices in reduced rowechelon form



#5
Jul2310, 08:00 PM

P: 1

radou is right: you do not need to swap row 2 and row 3, but "reduced row echelon form" has a formal definition and it is necessary to swap row 2 with row 3 to put c) in that form.



#6
Jul2410, 09:05 AM

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P: 39,491

Well, I agree with the last part of what jalexanal said but, as a result, I would have to say "radou is wrong"! Just for solving equations or related problems, the order of rows does not matter but for this problem, to tell whether or not the matrices are in "reduced row echelon" form, it does matter. In reduced row echlon form, there must be no rows below a given row with first nonzero member further to the left.



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