How Strong is the Electric Field Between Two Charged Plates?

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SUMMARY

The strength of the electric field between two charged plates separated by 0.01 cm can be calculated using the formula E = V/d. In this scenario, one plate has a potential of -20V and the other 0V, resulting in a potential difference of 20V. By substituting the values into the formula, E = (20V)/(0.0001m), the electric field strength is determined to be 2 x 10^5 V/m, or 200,000 volts per meter.

PREREQUISITES
  • Understanding of electric potential and electric fields
  • Familiarity with the formula E = V/d
  • Knowledge of unit conversions (cm to m)
  • Basic principles of electrostatics
NEXT STEPS
  • Research the concept of electric field lines and their properties
  • Learn about the effects of plate area on electric field strength
  • Explore applications of electric fields in capacitors
  • Study the relationship between electric fields and forces on charged particles
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in understanding electrostatics and electric field calculations.

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Two plates are placed .01 cm apart. One plate has a potential of -20V and the other has a potential of 0V. What is the strength of the electric field between them?
 
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never mind i got it
 


The strength of the electric field between the two plates can be calculated using the formula E = V/d, where E is the electric field strength, V is the potential difference between the plates, and d is the distance between the plates. In this case, the distance between the plates is 0.01 cm (or 0.0001 m) and the potential difference is 20V. Plugging these values into the formula, we get E = (20V)/(0.0001m) = 2 x 10^5 V/m. This means that the electric field strength between the two plates is 2 x 10^5 volts per meter.
 

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