Contour integral

Dick

Beg to differ. The a^2 term looks like (exp(a)+exp(-a))/a^2. I call that EVEN in rho. And (exp(a)-exp(-a))/a^3 is also even. Flip a to -a and see what happens... Exponentials are NOT ODD.

MadMax

nevermind........

MadMax

woo!!! I think i just understood what you meant. I was just too dense to see. if we convert the exponentials into sin and cos we are sorted! thanks a million dick, should be fine now :)

Dick

Good. Once you're ok with the extension to the whole real line, you'll have to break them up again into + and - imaginary parts to get the correct contours, right?