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Variable Voltage Source |
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| Feb27-07, 11:06 AM | #1 |
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Variable Voltage Source
1. The problem statement, all variables and given/known data
As the voltage in the circuit shown below is increased (but not to the breakdown voltage), the capacitance ![]() a. increases. b. decreases. c. does not change. d. increases, decreases, or does not change, depending on the charge on the plates of the capacitor. e. does none of these. 2. Relevant equations C = Q/V or C = (epsilon_0*A)/(d) 3. The attempt at a solution If the voltage increases at a specific rate, then the charge would also increase since Q and V are directly proportional and the ratio between the two is a constant. Therefore, the capacitance does not change???? Thanks. |
| Feb27-07, 11:25 AM | #2 |
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The capacitance should remain the same as it is a function of geometry and the material between the plates.
C = (epsilon * A) /d |
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