# inverse functions

by Ry122
Tags: functions, inverse
 P: 516 how do i find f(x)^-1 of y=4x+9/2x-3 the answer in the back of the text book is f(x)^-1=3x+9/2x-4
 P: 530 Show your attempt at a solution, or pay me 1 dollar for doing your homework for you (your choice).
 P: 516 2x=4x+9/y + 3y/y 2x=4x+9+3y/y How do i move 4x to the other side?
P: 530

## inverse functions

is 9/2x in your original post 9/(2x)? Just want to check.
 P: 516 Heres the full working out: y(2x-3)=4x+9 2x-3=4x+9/y 2x=4x+9/y + 3 2x=4x+9/y + 3y/y
 P: 530 You gotta learn to put brackets in your eqns. There's no way anyone could have understood your original problem without the brackets. y(2x-3)=4x+9 x(2y-4)-3y=9 x=(9+3y)/(2y-4)
 P: 516 Sorry to bother u again but how do u get from y(2x-3)=4x+9 to x(2y-4)-3y=9
 P: 530 expand and collect terms in x y(2x-3)=4x+9 -> y2x-3y=4x+9 -> x(2y)-3y=x(4)+9 -> x(2y-4)-3y=9

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