radius of convergence

cokezero

[b]1. The radius of convergence of the power series the sum n=1 to infinity of (3x+4)^n / n is

a 0
b 1/3
c 2/3
d 3/4
e 4/3

[b]2. the sum n=1 to infinity of (3x+4)^n / n



[b]3. no idea

do the ration test to get abs value 3x+4 < 1 ?

Mystic998

The ratio test is indeed the way to go. It's always a good place to start when the nth term of the series involves n! or a constant to the nth power.

cokezero

i know but what do i do to get from the ratio test to the radius of convergence?

Data

The ratio test says that [itex]\sum_{n=1}^\infty a_n[/itex] is abs. convergent if

[tex]\lim_{n \rightarrow \infty} \frac{|a_{n+1}|}{|a_n|} < 1,[/tex]

and divergent if the limit is greater than 1 (assuming in both cases that the limit exists, of course).

So find out for what [itex]x[/itex] your series converges using that test.

cokezero

yes, so i have

lim n --> oo ((3x + 4)^(n+1)/ (n +1)) * (n/ (3x +4)^n)

which simplifies to lim (3x + 4) (n/ (n+1))

so is it abs value (3x+4) < 1 if it converges? but i dont think i have this right b/c none of the answer choices fit to make this statement true.

a) 0
b) 1/3
c) 2/3
d) 3/4
e) 4/3

HallsofIvy

You havent finished yet. You need x, not 3x+4. Saying that |3x+4|< 1 means -1< 3x+4< 1. Now what interval does x lie in? What is the length of that interval? Of course, the "radius" of convergence is half the length of the interval of convergence.