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How to find the maximum velocity and maximum acceleration?

by dumpman
Tags: acceleration, maximum, velocity
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dumpman
#1
Apr8-07, 10:11 PM
P: 17
1. The problem statement, all variables and given/known data
The position of a particle moving along an x axis is given by x=12t^2-2t^3, what is the maximum positive coordinate, velocity and acceleration reached by the particle?

2. Relevant equations



3. The attempt at a solution
I took derivative of the quadratic and got V=24t-6t^2 and set it =0, then i solve for t and substituted in x=12t^2-2t^3 to get the max. positive coordinate.
But I dont know what to do to solve for the max velocity and acceleration
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Mindscrape
#2
Apr8-07, 10:17 PM
P: 1,875
You have the velocity as a function of time, just like you had the position as a function of time.
dumpman
#3
Apr8-07, 10:58 PM
P: 17
more hints?

Mindscrape
#4
Apr8-07, 11:09 PM
P: 1,875
How to find the maximum velocity and maximum acceleration?

Why not repeat the same process for your function of velocity?
dumpman
#5
Apr9-07, 10:38 AM
P: 17
Oh, so i set a=0 to find max velocity, but then what do I do to find the max acceleration?
Mindscrape
#6
Apr9-07, 11:14 AM
P: 1,875
Find the derivative of acceleration as a function of time and set it to zero. The physical term for the fourth derivative time is called jerk.


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