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Density of states |
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| May29-07, 06:04 PM | #1 |
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Density of states
Can someone explain to me why the density of states in 2D and 1D includes a step function? I have calculated the DOS in 2D to be:
[tex] D_2(E) = \frac{m_e}{\pi \hbar^2} [/tex] but in my book there a sum over step functions included so that the expression is: [tex] D_2(E) = \frac{m_e}{\pi \hbar^2} \sum_m \theta(E - E_m). [/tex] What does that step function do? It has something to do with the fact that there are a number of quantized states too right? Thanks |
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