
#1
May2907, 06:04 PM

P: 129

Can someone explain to me why the density of states in 2D and 1D includes a step function? I have calculated the DOS in 2D to be:
[tex] D_2(E) = \frac{m_e}{\pi \hbar^2} [/tex] but in my book there a sum over step functions included so that the expression is: [tex] D_2(E) = \frac{m_e}{\pi \hbar^2} \sum_m \theta(E  E_m). [/tex] What does that step function do? It has something to do with the fact that there are a number of quantized states too right? Thanks 


Register to reply 
Related Discussions  
Density of States  Atomic, Solid State, Comp. Physics  4  
Density of states??  Quantum Physics  1  
Density of states  Atomic, Solid State, Comp. Physics  3  
what is the essentail difference between local density of states and density of state  Atomic, Solid State, Comp. Physics  2  
Help, Density of States  Atomic, Solid State, Comp. Physics  1 