Register to reply

Block on a toboggan

Tags: block, toboggan
Share this thread:
Jul19-07, 11:05 PM
P: 8
I am confused about how to approach this question.

A 4.0 kg toboggan rests on a frictionless icy surface, and a 2.0 kg block rests on
top of the toboggan. The coefficient of static friction m
s between the block and the surface of the toboggan is 0.60, whereas the kinetic friction coefficient is 0.51. The block is pulled by a 30 N-horizontal force as shown. What are the magnitudes and directions of the resulting accelerations of the block and the toboggan?

If I calculate the acceleration of the box as so: Fpull- Ffriction = Fnet = ma
using the kinetic friction coefficient and solve for acceleration. Does that make sense.. and how then do I approach the acceleration of the toboggan?
Phys.Org News Partner Science news on
Sapphire talk enlivens guesswork over iPhone 6
Geneticists offer clues to better rice, tomato crops
UConn makes 3-D copies of antique instrument parts

Register to reply

Related Discussions
Toboggan Speed Theory General Physics 11
Box on a Toboggan - Newton's Laws Introductory Physics Homework 2
Toboggan down hill, FIND ANGLE? Introductory Physics Homework 11
Variable mass of a toboggan down a slope Advanced Physics Homework 1
Toboggan down icy slope Introductory Physics Homework 9