Understanding GSW 2.2.3: Questions on Vertexoperators and Symmetric Traces

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SUMMARY

The discussion focuses on GSW 2.2.3, specifically addressing the transformation law generated by the L_m's of the Virasoro algebra and the conditions for the tensor zeta to be symmetric and traceless. The transformation law tau -> tau -ie^{im tau} arises from the conformal transformations generated by the L_m's, which differ from the conserved charges discussed earlier. Additionally, the conditions k_mu zeta^munu = 0 and tr zeta = 0 imply that the tensor zeta is symmetric, as it remains invariant under the exchange of its indices.

PREREQUISITES
  • Understanding of GSW (Green-Schwarz-Witten) formalism
  • Familiarity with the Virasoro algebra and its generators
  • Knowledge of tensor properties, specifically symmetric and traceless tensors
  • Basic concepts of conformal transformations in theoretical physics
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  • Explore the implications of conformal transformations in string theory
  • Learn about the classification of tensors, focusing on symmetric and traceless conditions
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This discussion is beneficial for physics students, particularly those studying string theory, theoretical physicists working with conformal field theories, and researchers interested in the mathematical properties of tensors in high-energy physics.

Rene Meyer
Hello,

I stumbled about two things in GSW section 2.2.3 on Vertexoperators,
that I don't really understand.

The first one is GSW's statement just before 2.2.54, p. 88, that the
L_m's of the Virasoro algebra generate transformations like

tau -> tau -ie^{im tau}

... From what was said on p. 65 of the generators of the residual
symmetry and on p. 72 from the Virasoro generators I know that these
should be conserved charges, thus generating some transformations with
f(sigma^+) = e^imsigma^+ and f(sigma^-) = e^imsigma^-, which is at
sigma = 0 just e^imtau. But how to get from this result to the above
transformation law?

The second one is the statement on p. 92 that for the two conditions
k_mu zeta^munu = 0 and tr zeta = 0 the tensor zeta should be a
symmetric traceless tensor. Tracelessness is clear, but how to show
that under this condition the tensor should be symmetric?

I hope that these questions are not too elementary, but as I am new
with the string stuff, many elementary things bother me most,
sometimes.

René.

--
René Meyer
Student of Physics & Mathematics
Zhejiang University, Hangzhou, China
 
Physics news on Phys.org
On Wed, 31 Mar 2004, Rene Meyer wrote:

> The first one is GSW's statement just before 2.2.54, p. 88, that the
> L_m's of the Virasoro algebra generate transformations like
>
> tau -> tau -ie^{im tau}[/color]

To see this just go the other way round. Check that a field of conformal
weight J has the commutator given in (2.2.54).

> The second one is the statement on p. 92 that for the two conditions
> k_mu zeta^munu = 0 and tr zeta = 0 the tensor zeta should be a
> symmetric traceless tensor. Tracelessness is clear, but how to show
> that under this condition the tensor should be symmetric?[/color]

Symmetry follows implicitly from the form of formula (2.2.66), where
antisymmetric components of zeta do not contribute. k_m zeta^mn = 0
is responsible for the statement "... to be the polarization tensor..."
because this removes the unphysical timelike polarization.
 


Hello René,

Thank you for sharing your questions on GSW 2.2.3 and vertex operators. I will do my best to provide some clarification on these topics.

Regarding the first question about the transformation law, it is important to note that the L_m's of the Virasoro algebra are not the same as the conserved charges mentioned on p. 65 and p. 72. The L_m's are generators of the conformal transformations, while the conserved charges are generators of the residual symmetries. Therefore, the transformation law tau -> tau -ie^{im tau} is a result of the conformal transformations generated by the L_m's, not the residual symmetries.

For your second question, the condition k_mu zeta^munu = 0 and tr zeta = 0 implies that the tensor zeta is traceless and satisfies the condition zeta^munu = zeta^numu. This means that the tensor is symmetric. To see this, you can use the definition of a symmetric tensor, which states that a tensor is symmetric if it is invariant under the exchange of its indices. In this case, exchanging the indices mu and nu in zeta^munu will not change the tensor since zeta^munu = zeta^numu. Therefore, under the given conditions, the tensor zeta is both traceless and symmetric.

I hope this helps clarify your questions. If you have any further inquiries, please feel free to ask.
 

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