
#1
Aug207, 06:18 PM


#2
Aug207, 11:16 PM

Sci Advisor
HW Helper
Thanks
P: 25,173

Am I confused? If the figure is supposed to be a rectangle, then all of the triangles are isosceles. So 2a+89=180 and 2b+91=180. a>b. Am I missing something that is making this hard?




#3
Aug307, 04:09 AM

HW Helper
P: 3,353

We don't know that the angles at the corners are right angles.




#4
Aug307, 08:35 AM

Sci Advisor
HW Helper
Thanks
P: 25,173

Geometry Problem
If its an arbitrary quadrilateral then a>b is not necessarily true. Start drawing nonrectangular cases.



Register to reply 
Related Discussions  
Geometry problem  General Math  14  
Geometry problem  General Math  1  
a problem in geometry  Introductory Physics Homework  7  
Geometry problem!!  General Math  5  
Geometry Problem  General Math  3 