computing the order of a group


by Benzoate
Tags: computing, order
Benzoate
Benzoate is offline
#1
Sep6-07, 08:42 AM
P: 569
1. The problem statement, all variables and given/known data

Let a be an element of a group an let |a| = 15. Compute the orders of the following elements of G

a) a^3, a^6, a^9, a^12

2. Relevant equations



3. The attempt at a solution

for the first part of part a, would a^3 be <a^3>=<e,a^3,a^6,a^9,a^12,a^15,a^18,a^21,a^24,a^27,a^30, a^33,a^36,a^39,a^42>
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NateTG
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#2
Sep6-07, 09:11 AM
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|a|=15 means that 15 is the lowest power of a that is equal to the identity.

So, for example,
[tex]a^{42}=a^{15}\times a^{15} \times a^{12}=e \times e \times a^{12}=a^{12}[/tex]
so you've got too many things in your list.
matt grime
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#3
Sep6-07, 01:33 PM
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What I want to know is why the OP stopped after a^42 in particular. I mean going beyond a^15 is clearly wrong, but why stop at a^42? Is that the 15th power of a^3? I think so, from quickly scanning the list.


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