
#55
Sep1407, 04:30 PM

P: 397

oops.
man im bad.. 



#56
Sep1407, 04:33 PM

P: 397

dx = vocos(theta)vosin(theta)/(1/2)gcos(phi)  (1/2)gsin(phi)(vosin(theta)/(1/2)gcos(phi))^2
on the right side i can cancel out the (1/2) on the bottom and top, as well as the g, giving, dx = vocos(theta)vosin(theta)/(1/2)gcos(phi)  sin(phi)(vosin(theta)/cos(phi))^2 



#57
Sep1407, 04:35 PM

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#58
Sep1407, 04:38 PM

P: 397

oops again.
so im left with dx = vocos(theta)vosin(theta)/(1/2)gcos(phi)  sin(phi)(vo^2 sin(theta) ^2 / (1/2) g (cos(phi)^2) 



#59
Sep1407, 04:43 PM

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#60
Sep1407, 04:45 PM

P: 397

will trig identities apply since theta and phi are present?




#61
Sep1407, 04:46 PM

P: 397

im confused how one would ever get, for example : cos (theta + phi) through simplifying




#62
Sep1407, 05:04 PM

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#63
Sep1407, 05:06 PM

P: 397

i found that cos (a+b) = cosacosb +/ sinasinb... but i dont have that relationship anywhere




#64
Sep1407, 05:09 PM

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#65
Sep1407, 05:14 PM

P: 397

k im at
dx= vo^2sin(theta)*(cos(theta)sin(phi)) / (1/2)cos(phi)^2(sin(theta)) 



#66
Sep1407, 05:21 PM

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#67
Sep1407, 05:22 PM

P: 397

i cant factor out a vo^2?




#68
Sep1407, 05:23 PM

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#69
Sep1407, 05:25 PM

P: 397

i edited that in by mistake. i meant to put that in the numerator.
dx= vo^2sin(theta)*(cos(theta)sin(phi)sin(theta) / (1/2)gcos(phi)^2 



#70
Sep1407, 05:27 PM

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#71
Sep1407, 05:31 PM

P: 397

ya, you mean i didnt multiply it by (1/2)gcos(phi)^2?




#72
Sep1407, 05:50 PM

P: 397

ignore that last one



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