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commutation relations |
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| Oct1-07, 11:07 PM | #1 |
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commutation relations
i need to find the commutation relation for:
[tex] [x_i , p_i ^n p_j^m p_k^l] [/tex] I could apply a test function g(x,y,z) to this and get: [tex]=x_i p_i ^n p_j^m p_k^l g - p_i ^n p_j^m p_k^l x_i g [/tex] but from here I'm not sure where to go. any help would be appreciated. |
| Oct1-07, 11:35 PM | #2 |
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You don't need a test function. All you need are the following:
(i) [itex] [x_i,p_j] = i \hbar \delta_{i,j} [/itex] (ii) [itex] [AB,C]=A[B,C]+[A,C]B [/itex] |
| Oct2-07, 12:46 AM | #3 |
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should that be [itex] [x_i,p_j] = i \hbar \delta_{i,j} [/itex]?
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| Oct2-07, 02:12 AM | #4 |
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commutation relations
i guess a more reasonable question would i expand [itex][x_i,p_i^n][/itex]
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| Oct2-07, 10:44 AM | #5 |
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If you use the second relationship in post #2 recursively, you will discover a general form for the commutator [itex][x_i,p_i^n] [/itex].
Try p^2 and p^3 first - you'll see what I mean. PS: Yes, there was a "bad" minus sign which I've now fixed. |
| Oct2-07, 10:53 AM | #6 |
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how about: [itex][x_i,p_i^n]=ni \hbar p_i ^{n-1} [/itex]
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| Oct3-07, 07:28 PM | #7 |
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Looks good. Now you're just a step or two away from the answer to the original question.
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