## car turning

1. The problem statement, all variables and given/known data
When you take your 1100-kg car out for a spin, you go around a corner of radius 55m with a speed of 15m/s. Assuming your car doesn't skid, what is the force exerted on it by static friciton?

2. Relevant equations
f$$_{}c$$=ma$$_{}c$$
f$$_{}c$$=mv$$^{}2$$/r
$$\sumf=ma$$

3. The attempt at a solution
$$\sum$$f=ma
f$$_{}s$$=mv$$^{}2$$/r
f$$_{}s$$=300

300=$$\mu$$$$_{}s$$mg
300=$$\mu$$$$_{}s$$(1100)(908)
$$\mu_{}s$$=0.027

but apparantley it's supposed to be 4.5
what happened?

 PhysOrg.com science news on PhysOrg.com >> Heat-related deaths in Manhattan projected to rise>> Dire outlook despite global warming 'pause': study>> Sea level influenced tropical climate during the last ice age
 Recognitions: Homework Help How did you get 300? And why are you calculating the coefficient of friction? The question only asks for the force.