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car turning

 
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Oct11-07, 09:12 PM   #1
 

car turning


1. The problem statement, all variables and given/known data
When you take your 1100-kg car out for a spin, you go around a corner of radius 55m with a speed of 15m/s. Assuming your car doesn't skid, what is the force exerted on it by static friciton?


2. Relevant equations
f[tex]_{}c[/tex]=ma[tex]_{}c[/tex]
f[tex]_{}c[/tex]=mv[tex]^{}2[/tex]/r
[tex]\sumf=ma[/tex]

3. The attempt at a solution
[tex]\sum[/tex]f=ma
f[tex]_{}s[/tex]=mv[tex]^{}2[/tex]/r
f[tex]_{}s[/tex]=300

300=[tex]\mu[/tex][tex]_{}s[/tex]mg
300=[tex]\mu[/tex][tex]_{}s[/tex](1100)(908)
[tex]\mu_{}s[/tex]=0.027

but apparantley it's supposed to be 4.5
what happened?
 
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Oct11-07, 09:42 PM   #2
 
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How did you get 300?

And why are you calculating the coefficient of friction? The question only asks for the force.
 
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