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car turning |
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| Oct11-07, 09:12 PM | #1 |
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car turning
1. The problem statement, all variables and given/known data
When you take your 1100-kg car out for a spin, you go around a corner of radius 55m with a speed of 15m/s. Assuming your car doesn't skid, what is the force exerted on it by static friciton? 2. Relevant equations f[tex]_{}c[/tex]=ma[tex]_{}c[/tex] f[tex]_{}c[/tex]=mv[tex]^{}2[/tex]/r [tex]\sumf=ma[/tex] 3. The attempt at a solution [tex]\sum[/tex]f=ma f[tex]_{}s[/tex]=mv[tex]^{}2[/tex]/r f[tex]_{}s[/tex]=300 300=[tex]\mu[/tex][tex]_{}s[/tex]mg 300=[tex]\mu[/tex][tex]_{}s[/tex](1100)(908) [tex]\mu_{}s[/tex]=0.027 but apparantley it's supposed to be 4.5 what happened? |
| Oct11-07, 09:42 PM | #2 |
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Recognitions:
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How did you get 300?
And why are you calculating the coefficient of friction? The question only asks for the force. |
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