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Two Converging Lense Questions Please Help |
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| May8-03, 09:43 AM | #1 |
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Two Converging Lense Questions Please Help
For a lens of focal length f, what value of the distance between the object and the lens[D0] would give an image with a magnification of one?
Is it possible to obtain a non-inverted image with a converging spherical lens? Explain please? Any response would be greatly appreciated, and I would like to thank anyone for their response to this thread in advance. |
| May8-03, 04:44 PM | #2 |
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Hi JM2107,
to answer questions like this, you could use use 2 methods: 1) Draw 3 rays, remembering that... ... focal ray becomes parallel ray ... parallel ray becomes focal ray ... central ray is not refracted 2) Use the Law of lenses: 1/o + 1/i = 1/f where o = distance of object from lens i = distance of image from lens f = focal length Got it? [;)] |
| May8-03, 06:47 PM | #3 |
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Recognitions:
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It is not possible to obtain a non inverted image using a single converging lens. It is therefore not possible to obtain a magnification of 1, though it is possible to obtain a magnification of -1. (Inverted images have a negative magnification by convention).
The reason for this is purely geometrical. Arcnets outlined a standard graphical method of seeing why this is. |
| May9-03, 03:53 PM | #4 |
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Two Converging Lense Questions Please Help |
| May9-03, 09:17 PM | #5 |
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Here's the answer:
Yes, it is possible to obtain a non-inverted image with a converging lens. As long as the object is between the focal length point and the lens it is possible. Of course this would be a virtual image and the image would be magnified. m=-d(image)/d(object) If m=1 than we have an equation where we can put d (object) = - d (image). Since 1/f = 1/d (object) + 1/d (image) and since d (object) = - d (image), therefore 1/f = 0 So there is no distance that would give a magnification of one. |
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