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Thermal Expansion of Gas in a Tank 
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#1
Oct2107, 01:27 PM

P: 2

1. The problem statement, all variables and given/known data
An underground gasoline tank at 54°F can hold 1100 gallons of gasoline. If the driver of a tanker truck fills the underground tank on a day when the temperature is 82°F, how many gallons, according to his measure on the truck, can he pour in? Assume that the temperature of the gasoline cools to 54°F on entering the tank. 2. Relevant equations (delta)Length = 3(alpha) * Volume(initial) * (delta)Temp i found the value alpha for gasoline to be 9.6e4 3. The attempt at a solution 3(9.6e4)(28)(1100)=delta(L)=88.7 thus the amount he could pour in is 1188.7 for some reason this isn't the answer though... i'm not really sure what i'm doing wrong 


#2
Oct2107, 01:48 PM

Mentor
P: 41,579

The equation for volume expansion will look like this:
[tex]\Delta V = \beta V_0 \Delta T[/tex] where [itex]\beta[/itex] is the volume coefficient of expansion, which would be about 3 times the linear coefficient. Are you sure you found the linear coefficient of expansion for gasoline? 


#3
Oct2107, 02:53 PM

P: 2

You're right.. thank you so much. The 9.6e4 already accounted for the times 3, and thus was the volume coefficient of expansion. I guess you couldn't really make one for gasoline anyway. Thanks again.



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