
#1
Oct2207, 09:01 PM

P: 93

1. The problem statement, all variables and given/known data
By considering different paths of approach, show that the function below has no limit as (x,y) > (0,0). f(x,y) =  x / sqrt(x^2 + y^2). 2. Relevant equations This is the problem! I do not know the different techniques to find the limits of functions of more than one variable. My book only shows examples of cases where you can get the answer by substituting y=mx or y=kx^2. 3. The attempt at a solution I tried the above substitutions but they don't work. 



#2
Oct2207, 10:05 PM

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P: 25,178

Why do you say y=mx doesn't work? You don't even get a limit for m=0.




#3
Oct2207, 10:32 PM

P: 93

When we substitute y=mx, we get 1/sqrt(1+m^2). So when m=0, the limit will be 1 won't it?




#4
Oct2207, 10:38 PM

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P: 25,178

Limits of functions of 2 variables
Depends on whether x is positive or negative. sqrt(x^2)=abs(x).




#5
Oct2207, 10:40 PM

P: 93

I didn't see that. Thanks!!




#6
Mar1208, 05:34 AM

P: 1

Hey. how do you solve:
lim(x,y)>(0,pi/2) ( x/cos(y) ) lots of thanks 



#7
Mar1208, 06:04 AM

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P: 38,904

Have you noticed that these problems do NOT ask you to find the limit but to show that the limit does not exist? That is much simpler. Here, what limit do you get if you first let x go to 0, then let y go to [itex]\pi/2[/itex]? What limit do you get if you first let y go to [itex]\pi/2[/itex], then let x go to 0? What does that tell you?



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