Why? question about optical encoder

engineer23

Why is the outermost ring of an optical encoder the least significant bit? Is this somehow related to frequency?

NoTime

There is more length in the outside ring.
For a sensor of any given resolution the wider the disk the more lines that can be scribed on it.
While in a way this relates to frequency, it is more about sensor resolution.

rbj

just curious, does your optical encoder use Gray code? it should. if it does, the two LSBs (of Gray code) will have the same "frequency" but will be 90^o outa phase. just like the encoders of the earlier mice.

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engineer23	Why? question about optical encoder Tweet Why is the outermost ring of an optical encoder the least significant bit? Is this somehow related to frequency?

NoTime Recognitions: Gold Member Homework Help Science Advisor	There is more length in the outside ring. For a sensor of any given resolution the wider the disk the more lines that can be scribed on it. While in a way this relates to frequency, it is more about sensor resolution.