
#1
Nov1407, 08:08 PM

P: 67

1. The problem statement, all variables and given/known data
Find the final velocity of the object if it is initially moving along the x axis with average velocity of 62 m/s. Other information mass=.462kg time=5s average force = 0.8N impulse=4 2. Relevant equations F=m(VfVi)/t 3. The attempt at a solution I use the equation like this (0.8N)=(.426kg)(Vf+62m/s)/(5s) =61.13m/s Is that right? 



#2
Nov1407, 08:42 PM

P: 23

I dont know why they gave you impulse, you can solve the problem with this equation:
Vf = Vi + at where Vf=final velocity, Vi=initial velocity, a=acc. and t=time. Remember  the acc. is .8/.462 because F=ma, so a=F/m. Good luck! 



#3
Nov1407, 08:47 PM

P: 67

Vf = Vi + at
Vf= (62m.s) + (.8/.462)(5) = 53.3 m/s Thats what I got but it isn't right. I'm sure I didn't up the algebra, did I plug something in wrong? 



#4
Nov1407, 08:50 PM

P: 23

Calculating final Velocity
well then i guess your initial approach is correct. the equation I gave might not work cuz i didnt read the part that said "avg velocity". I think your 61 is correct



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