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Limits of Average Rates of Change |
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| Dec14-07, 10:35 PM | #1 |
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Limits of Average Rates of Change
I'm not looking for an answer to a specific question, but I want to know in general how to evaluate the limit of average rates of change.
1. The problem statement, all variables and given/known data lim[tex]_{}h \rightarrow0[/tex] f (x + h) - f (x) / h 2. Relevant equations f(x) = x^2 , x = 1 3. The attempt at a solution I really don't know what to do. Obviously we need the denominator not equal to 0. An example in my book showed them multiply by 1 by multiplying the numerator and denominator by the conjugate since the numerator had roots...but this has no roots. |
| Dec14-07, 11:01 PM | #2 |
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I don't want to do your homework, so I'll do f(x) = x^3.
[tex]\lim_{h\rightarrow 0} \frac{f(x+h)-f(x)}{h}[/tex] [tex]\lim_{h\rightarrow 0} \frac{(x+h)^3-x^3}{h}[/tex] [tex]\lim_{h\rightarrow 0} \frac{x^3 + 3x^2h + 3xh^2 + h^3 - x^3}{h}[/tex] [tex]\lim_{h\rightarrow 0} \frac{3x^2h + 3xh^2 + h^3}{h}[/tex] [tex]\lim_{h\rightarrow 0} 3x^2 + 3xh + h^2[/tex] [tex]=3x^2[/tex] |
| Dec14-07, 11:07 PM | #3 |
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If it says for example x = 1, all you do f (1) and evaluate?
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| Dec15-07, 12:02 AM | #4 |
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Limits of Average Rates of Change
Right, so in the example I did, f ' (1) = 3, f ' (2) = 12 etc.
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| Dec15-07, 12:14 AM | #5 |
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Well Since you know that you must evaluate at x=1, you can do two things. Either do as nicksauce did, and sub in x=1 at the end, or simply evaluate
[tex]\lim_{h\to 0} \frac{(1+h)^2 - 1^2}{h}[/tex] Directly. |
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