How Far Can a Mass Be Placed on a Bar Before the Supporting Wire Breaks?

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SUMMARY

The discussion focuses on determining the maximum distance from the wall at which a mass M can be placed on a uniform horizontal bar of length 3 m and weight 232 N, supported by a wire at a 35-degree angle. The wire can withstand a maximum tension of 537 N, while the weight of mass M is 355 N. The solution involves applying static equilibrium principles, specifically considering both rotational and translational forces, and utilizing a free body diagram to visualize the forces acting on the system.

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A uniform horizontal bar of length L = 3 m and weight 232 N is pinned to a vertical wall and supported by a thin wire that makes an angle of theta = 35o with the horizontal. A mass M, with a weight of 355 N, can be moved anywhere along the bar. The wire can withstand a maximum tension of 537 N. What is the maximum possible distance from the wall at which mass M can be placed before the wire breaks?

I believe that this is an equilibrium problem, my problem is that i don't know where to start.

Any help would be appreciated.
 
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This is a static equilibrium problem. There are both rotational and translational considerations. The point pinned to the wall gives a constraint force. The wire gives a force at a moment. The weight of the bar gives a force about a moment. The weight of the mass M gives a force about a moment. Consider rotational equilibrium about the point pinned to the wall.

Draw a free body diagram.
 
I got this one, forgot I asked for help. Thanks!
 

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