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Latex questionby kdv
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#1
Jan1308, 03:11 PM

P: 329

I am not sure if this is the right place to post a Latex question. If not, tell me where I should go.
I would like to put equations inside a box. Now, I have found two ways to do this butthey work only for single line equations. The best method is to simply put the equations between boxed braces, i.e. \boxed{ equation} this works if I am in an equation array i.e. \begin{equation} \boxed{equation} \end{equation} I have tried the same thing in an eqnarray but I get compilations errors. I would like to have equations spanning several lines which would be inside a box. Anybody can help? Thanks 


#2
Jan1308, 03:25 PM

PF Gold
P: 1,434




#3
Jan2708, 07:57 PM

P: 329

[tex] \begin{equation*} \addtolength{\fboxsep}{5pt} \boxed{ \begin{gathered} \Pi_{i=1}^m \int d^4x_i \, e^{i (k \cdot x)_i} ~\Pi_{j=1}^n \int d^4y_j \, e^{+ i (p \cdot y)_j} \\ <0 T\{ \phi(x_1) \ldots \phi(x_m) \phi(y_1) \ldots \phi(y_n) \} 0> \\ = \biggl( \Pi_{i=1}^m \frac{i \sqrt{Z}}{k_i^2  m^2} \biggr) \biggl(\Pi_{j=1}^n \frac{i \sqrt{Z}}{p_j^2  m^2} \biggr) ~<\vec{p}_1 \ldots \vec{p_n}i T \vec{k_1} \ldots \vec{k_m}> \end{gathered} } \end{equation*} [/tex] It worked!!!!!! (For anybody interested, left click on the equation to see the source code) 


#4
May1310, 11:17 AM

P: 1

Latex question
Thanks a lot for this tip kdv I'd been wondering how to get boxes around multiline equations.
Also, for alignment you can use the 'split' environment rather than 'gathered'. [tex] \begin{equation*} \addtolength{\fboxsep}{10pt} \boxed{ \begin{split} \int \frac{d^D P}{(2\pi)^D} \frac{{\cal P}_n(P)} {P^{2\alpha}(PQ)^{2\beta}} = &\frac{1}{(4\pi)^2}(Q^2)^{D/2\alpha\beta}\sum_{\sigma \ge 0}^{[n/2]} G(\alpha,\beta,n,\sigma) \cdot \\ &\cdot Q^{2\sigma} \left\{ \frac{1}{\sigma !} \left( \frac {\Box} {4} \right) ^\sigma {\cal P}_n(P)\right\}_{P=Q} \end{split} } \end{equation*} [/tex] For anybody compiling this remember to include \usepackage{amsmath} in your preamble and for this particular example also \usepackage{amssymb} for the D'Alembertian. Thanks again. 


#5
Jul1912, 07:40 PM

P: 35

kdv, thanks for posting your answer after finding it. Google funneled me here, and your post has helped me out.



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