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Diophantine Equation... |
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| Jan21-08, 05:14 PM | #1 |
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Diophantine Equation...
Solve the following equation:
[tex]x^y-y^x = y^z-x^z[/tex] where [tex]x\neq y[/tex] and x, y, z are positive. My first intuition was to solve this in terms of z using logarithms. Am I on the right track? |
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