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Limit of a sequence |
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| Jan22-08, 01:37 PM | #1 |
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Limit of a sequence
1. The problem statement, all variables and given/known data
Find the following limit: [tex]\lim_{n \rightarrow \infty}\frac{n}{\log_{10}{n}}[/tex] 3. The attempt at a solution It's easy to find the limit using L'Hospital rule (after having used Heine theorem to transform the sequence into a function): [tex]\lim_{x \rightarrow \infty}\frac{x}{\log_{10}{x}} = \lim_{x \rightarrow \infty}\frac{1}{\frac{1}{x\log{10}}} = +\infty[/tex] Is there any way of solving it without L'Hospital rule? If I was to use the definition, then for every K, there should be such n_0 that for every n>n_0, (n/log_10(n)) > K. But I don't know how to solve this inequality. Any help would be greatly appreciated, thanks in advance! |
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| Jan22-08, 03:12 PM | #2 |
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Recognitions:
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There are easily manageable subsequences like:
[tex]\frac{10^{10^k}}{\log_{10}10^{10^k}}=10^{10^k-k}[/tex] which clearly go to infinitely. You could also work through an epsilon-delta proof of l'Hospital's rule. |
| Jan22-08, 03:22 PM | #3 |
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The subsequence way of solving is elegant, i didn't realise it... thanks a lot!
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