| Thread Closed |
[SOLVED] squaring units |
Share Thread | Thread Tools |
| Feb8-08, 01:13 AM | #1 |
|
|
[SOLVED] squaring units
1. The problem statement, all variables and given/known data
When you calculate numerically something like q^2/4*Pi*Epsilon_0, do you square the units of q i.e. is it (q 1.602 176 487 × 10-19 C)^2 or q^2 1.602 176 487 × 10-19 C ? 2. Relevant equations 3. The attempt at a solution |
| Feb8-08, 01:55 AM | #2 |
|
|
if q = 1.602*10^-19C, then q^2 = {(1.602*10^-19)^2}C^2
|
| Feb8-08, 08:42 PM | #3 |
|
Recognitions:
|
A good way to see that you have to square units (or raise them to any power) is to consider the following "paradox".
Suppose you have $1. One dollar is just 100 cents: $1 = ¢100 If we take the square root of both sides but neglect to take the square root of the units (dollars and cents), we get $1 = ¢10! So, you have to take the square root of the units too, otherwise all of your dollars are only worth dimes, and all of your dimes are worth a dollar! (As attractive as that might sound, what do you want to bet that the banks would only treat your dollars as being dimes and not vice versa?) |
| Thread Closed |
| Thread Tools | |
Similar Threads for: [SOLVED] squaring units
|
||||
| Thread | Forum | Replies | ||
| squaring a vector? | General Math | 3 | ||
| Squaring a bra | Advanced Physics Homework | 8 | ||
| Parametric terms and squaring this function | Calculus | 0 | ||
| Maxwell related equations converted from MKSA units to Gaussian units | Classical Physics | 2 | ||