# double bar matrix element

by malawi_glenn
Tags: double, element, matrix
 HW Helper Sci Advisor P: 4,739 Is wondering if anyone knows if the modulus square of the double matrix element that arises in Wigner-Eckart theorem obeys the same "rule" as the ordinary does, if the operator is hermitian: $$||^2 = ||^2$$ if M is hermitian. Is then : $$||^2 = ||^2$$ ? --- I think it does, the Wigner-Eckart theorem states: $$\langle njm|T^k_q|n'j'm'\rangle =\langle nj||T_q||n'j'\rangle C^{jm}_{kqj'm'}$$ where $$C^{jm}_{kqj}$$ is a Clebsh gordan So I think things will work out, are someone sure about how these things work, please tell me :)

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