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Surface charge density |
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| Feb16-08, 09:18 AM | #1 |
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Surface charge density
A 10.0g piece of styrofoam carries a net charge of -.700 x 10^-6 C and floats above the center of a large horizontal sheet of plastic that has a uniform charge density on its surface. What is the charge per unit area on the plastic sheet?
I've been trying to think a way to model this with a Gaussian surface (without using integrals)...but doesn't seem to work. |
| Feb16-08, 09:27 AM | #2 |
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Hint: What electric field must the sheet of charge produce to support the styrofoam?
You can certainly use Gauss's law to find the field from a uniform sheet of charge, if you don't happen to know it. |
| Feb16-08, 09:51 AM | #3 |
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The electric force should balance out the force of gravity. Dividing that by the charge of the styrofoam ball should give the electric field. But I keep bumping into the distance squared quantity. How would I eliminate it?
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| Feb16-08, 10:00 AM | #4 |
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Surface charge densityWhat's the electric field from an infinite sheet of charge with some given surface charge density? |
| Feb16-08, 10:09 AM | #5 |
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The electric field should be E = o/2e, in which o is the surface charge density and e is the permittivity of free space. Then that would also imply that o = E*2e. The Electric field is equal to the electric force divided by the charge of the styrofoam ball....oh. I see. I got it now. Thanks for the help.
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| Oct25-08, 01:48 AM | #6 |
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Doc Al - PLEASE help me.
So I understand that the electric F equals the gravitational force. Then I divide that by the charge given in the problem to get the electric field. Now, to get the charge per unit area we use the equation E=sigma/2e0. We know the electric field so we rearrange the equation to solve for sigma because that is the charge/unit area factor we are looking for. So now I'm stuck with this equation: sigma = E * 2e0 I know the electric field and 2e0 but when I multiply these 2 together I get a wrong answer and a wrong SIGN as well. What am I doing wrong? |
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